Data:L11a65/Multivariable Alexander
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[math]\displaystyle{ -\frac{(t(1)-1) (t(2)-1) \left(4 t(2)^2-5 t(2)+4\right)}{\sqrt{t(1)} t(2)^{3/2}} }[/math]
[math]\displaystyle{ -\frac{(t(1)-1) (t(2)-1) \left(4 t(2)^2-5 t(2)+4\right)}{\sqrt{t(1)} t(2)^{3/2}} }[/math]