2 t ( 3 ) 3 − 2 t ( 1 ) t ( 3 ) 2 − 2 t ( 2 ) t ( 3 ) 2 − t ( 3 ) 2 + 2 t ( 1 ) t ( 3 ) + t ( 1 ) t ( 2 ) t ( 3 ) + 2 t ( 2 ) t ( 3 ) − 2 t ( 1 ) t ( 2 ) t ( 1 ) t ( 2 ) t ( 3 ) 3 / 2 {\displaystyle {\frac {2t(3)^{3}-2t(1)t(3)^{2}-2t(2)t(3)^{2}-t(3)^{2}+2t(1)t(3)+t(1)t(2)t(3)+2t(2)t(3)-2t(1)t(2)}{{\sqrt {t(1)}}{\sqrt {t(2)}}t(3)^{3/2}}}}
