Data:L11n282/Multivariable Alexander
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[math]\displaystyle{ \frac{(t(1)-1) (t(2)-1) (t(3)-1) \left(t(3)^2-t(3)+1\right)}{\sqrt{t(1)} \sqrt{t(2)} t(3)^{3/2}} }[/math]
[math]\displaystyle{ \frac{(t(1)-1) (t(2)-1) (t(3)-1) \left(t(3)^2-t(3)+1\right)}{\sqrt{t(1)} \sqrt{t(2)} t(3)^{3/2}} }[/math]