Planar Diagrams: Difference between revisions
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<!--$$?PD$$--> |
<!--$$?PD$$--> |
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{{HelpAndAbout| |
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{{HelpAndAbout1|n=1|s=PD}} |
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n = 2 | |
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⚫ | |||
n1 = 3 | |
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{{HelpAndAbout2|n=2|s=PD}} |
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in = <nowiki>PD</nowiki> | |
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⚫ | |||
⚫ | |||
{{HelpAndAbout3}} |
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⚫ | |||
<!--END--> |
<!--END--> |
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<!--$$?X$$--> |
<!--$$?X$$--> |
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<!--Robot Land, no human edits to "END"--> |
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{{HelpLine| |
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{{Help1|n=3|s=X}} |
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n = 4 | |
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⚫ | |||
in = <nowiki>X</nowiki> | |
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{{Help2}} |
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⚫ | |||
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Thus, for example, let us compute the determinant of the above knot: |
Thus, for example, let us compute the determinant of the above knot: |
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<!--$$K = PD[ |
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⚫ | |||
X[1,9,2,8], X[3,10,4,11], X[5,3,6,2], |
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⚫ | |||
];$$--> |
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<!--Robot Land, no human edits to "END"--> |
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{{ |
{{In| |
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n = 5 | |
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<pre style="color: red; border: 0px; padding: 0em"><nowiki>K = PD[X[1,9,2,8], X[3,10,4,11], X[5,3,6,2], X[7,1,8,12], X[9,4,10,5], X[11,7,12,6]];</nowiki></pre> |
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in = <nowiki>K = PD[ |
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{{In2}} |
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X[1,9,2,8], X[3,10,4,11], X[5,3,6,2], |
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X[7,1,8,12], X[9,4,10,5], X[11,7,12,6] |
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];</nowiki>}} |
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<!--END--> |
<!--END--> |
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<!--$$Alexander[K][-1]$$--> |
<!--$$Alexander[K][-1]$$--> |
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{{ |
{{InOut| |
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n = 6 | |
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<pre style="color: red; border: 0px; padding: 0em"><nowiki>Alexander[K][-1]</nowiki></pre> |
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in = <nowiki>Alexander[K][-1]</nowiki> | |
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out= <nowiki>-11</nowiki>}} |
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{{InOut3}} |
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<!--END--> |
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<!--$$?Xp$$--> |
<!--$$?Xp$$--> |
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{{HelpLine| |
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{{Help1|n=6|s=Xp}} |
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n = 7 | |
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⚫ | Xp[i,j,k,l] represents a positive (right handed) crossing between the edges labeled i, j, k and l starting from the incoming lower strand i and going counter clockwise through j, k and l. The upper strand is therefore oriented from l to j regardless of the ordering of {j,l}. Presently Xp is only lightly supported. |
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in = <nowiki>Xp</nowiki> | |
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{{Help2}} |
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⚫ | out= <nowiki>Xp[i,j,k,l] represents a positive (right handed) crossing between the edges labeled i, j, k and l starting from the incoming lower strand i and going counter clockwise through j, k and l. The upper strand is therefore oriented from l to j regardless of the ordering of {j,l}. Presently Xp is only lightly supported.</nowiki>}} |
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<!--END--> |
<!--END--> |
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<!--$$?Xm$$--> |
<!--$$?Xm$$--> |
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{{HelpLine| |
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{{Help1|n=7|s=Xm}} |
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n = 8 | |
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⚫ | Xm[i,j,k,l] represents a negative (left handed) crossing between the edges labeled i, j, k and l starting from the incoming lower strand i and going counter clockwise through j, k and l. The upper strand is therefore oriented from j to l regardless of the ordering of {j,l}. Presently Xm is only lightly supported. |
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in = <nowiki>Xm</nowiki> | |
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{{Help2}} |
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⚫ | out= <nowiki>Xm[i,j,k,l] represents a negative (left handed) crossing between the edges labeled i, j, k and l starting from the incoming lower strand i and going counter clockwise through j, k and l. The upper strand is therefore oriented from j to l regardless of the ordering of {j,l}. Presently Xm is only lightly supported.</nowiki>}} |
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<!--END--> |
<!--END--> |
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<!--$$?P$$--> |
<!--$$?P$$--> |
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{{HelpLine| |
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{{Help1|n=8|s=P}} |
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n = 9 | |
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in = <nowiki>P</nowiki> | |
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{{Help2}} |
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⚫ | |||
<!--END--> |
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For example, we could add an extra "point" on the Miller Institute knot, splitting edge 12 into two pieces, labeled 12 and 13: |
For example, we could add an extra "point" on the Miller Institute knot, splitting edge 12 into two pieces, labeled 12 and 13: |
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<!--$$K1 = PD[ |
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<!--$$K1 = PD[X[1,9,2,8], X[3,10,4,11], X[5,3,6,2], X[7,1,8,13], X[9,4,10,5], X[11,7,12,6], P[12,13]];$$--> |
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X[1,9,2,8], X[3,10,4,11], X[5,3,6,2], |
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X[7,1,8,13], X[9,4,10,5], X[11,7,12,6], |
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P[12,13] |
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];$$--> |
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<!--Robot Land, no human edits to "END"--> |
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{{ |
{{In| |
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n = 10 | |
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<pre style="color: red; border: 0px; padding: 0em"><nowiki>K1 = PD[X[1,9,2,8], X[3,10,4,11], X[5,3,6,2], X[7,1,8,13], X[9,4,10,5], X[11,7,12,6], P[12,13]];</nowiki></pre> |
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in = <nowiki>K1 = PD[ |
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{{In2}} |
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X[1,9,2,8], X[3,10,4,11], X[5,3,6,2], |
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X[7,1,8,13], X[9,4,10,5], X[11,7,12,6], |
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P[12,13] |
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];</nowiki>}} |
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<!--END--> |
<!--END--> |
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<!--$$Jones[K][q] == Jones[K1][q]$$--> |
<!--$$Jones[K][q] == Jones[K1][q]$$--> |
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{{InOut| |
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{{InOut1|n=10}} |
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n = 11 | |
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in = <nowiki>Jones[K][q] == Jones[K1][q]</nowiki> | |
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{{InOut2|n=10}}<pre style="border: 0px; padding: 0em"><nowiki>True</nowiki></pre> |
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out= <nowiki>True</nowiki>}} |
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{{InOut3}} |
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<!--END--> |
<!--END--> |
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<!--$$?Loop$$--> |
<!--$$?Loop$$--> |
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{{HelpLine| |
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{{Help1|n=11|s=Loop}} |
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n = 12 | |
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in = <nowiki>Loop</nowiki> | |
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{{Help2}} |
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⚫ | |||
<!--END--> |
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<!--$$A2Invariant[Loop[1]][q]$$--> |
<!--$$A2Invariant[Loop[1]][q]$$--> |
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<!--Robot Land, no human edits to "END"--> |
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{{InOut| |
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{{InOut1|n=12}} |
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n = 13 | |
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in = <nowiki>A2Invariant[Loop[1]][q]</nowiki> | |
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{{InOut2|n=12}}<pre style="border: 0px; padding: 0em"><nowiki> -2 2 |
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out= <nowiki> -2 2 |
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1 + q + q</nowiki> |
1 + q + q</nowiki>}} |
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{{InOut3}} |
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<!--END--> |
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Latest revision as of 17:08, 21 February 2013
In the "Planar Diagrams" (PD
) presentation we present every knot or link diagram by labeling its edges (with natural numbers, 1,...,n, and with increasing labels as we go around each component) and by a list crossings presented as symbols where , , and are the labels of the edges around that crossing, starting from the incoming lower edge and proceeding counterclockwise. Thus for example, the PD
presentation of the knot above is:
(This of course is the Miller Institute knot, the mirror image of the knot 6_2)
(For In[1] see Setup)
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Thus, for example, let us compute the determinant of the above knot:
In[5]:=
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K = PD[
X[1,9,2,8], X[3,10,4,11], X[5,3,6,2],
X[7,1,8,12], X[9,4,10,5], X[11,7,12,6]
];
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In[6]:=
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Alexander[K][-1]
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Out[6]=
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-11
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Some further details
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For example, we could add an extra "point" on the Miller Institute knot, splitting edge 12 into two pieces, labeled 12 and 13:
In[10]:=
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K1 = PD[
X[1,9,2,8], X[3,10,4,11], X[5,3,6,2],
X[7,1,8,13], X[9,4,10,5], X[11,7,12,6],
P[12,13]
];
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At the moment, many of our routines do not know to ignore such "extra points". But some do:
In[11]:=
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Jones[K][q] == Jones[K1][q]
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Out[11]=
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True
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Hence we can verify that the A2 invariant of the unknot is :
In[13]:=
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A2Invariant[Loop[1]][q]
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Out[13]=
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-2 2
1 + q + q
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