Planar Diagrams: Difference between revisions
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Thus, for example, let us compute the determinant of the above knot: |
Thus, for example, let us compute the determinant of the above knot: |
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X[1,9,2,8], X[3,10,4,11], X[5,3,6,2], |
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{{In| |
{{In| |
Revision as of 11:49, 30 August 2005
In the "Planar Diagrams" (PD
) presentation we present every knot or link diagram by labeling its edges (with natural numbers, 1,...,n, and with increasing labels as we go around each component) and by a list crossings presented as symbols where , , and are the labels of the edges around that crossing, starting from the incoming lower edge and proceeding counterclockwise. Thus for example, the PD
presentation of the knot above is:
(This of course is the Miller Institute knot, the mirror image of the knot 6_2)
(For In[1] see Setup)
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Thus, for example, let us compute the determinant of the above knot:
In[4]:=
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K = PD[X[1,9,2,8], X[3,10,4,11], X[5,3,6,2], X[7,1,8,12], X[9,4,10,5], X[11,7,12,6]];
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In[5]:=
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Alexander[K][-1]
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Out[5]=
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-11
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Some further details
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For example, we could add an extra "point" on the Miller Institute knot, splitting edge 12 into two pieces, labeled 12 and 13:
In[9]:=
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K1 = PD[X[1,9,2,8], X[3,10,4,11], X[5,3,6,2], X[7,1,8,13], X[9,4,10,5], X[11,7,12,6], P[12,13]];
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At the moment, many of our routines do not know to ignore such "extra points". But some do:
In[10]:=
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Jones[K][q] == Jones[K1][q]
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Out[10]=
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True
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Hence we can verify that the A2 invariant of the unknot is :
In[12]:=
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A2Invariant[Loop[1]][q]
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Out[12]=
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-2 2
1 + q + q
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